tolong dibantu, persamaan eksponensial
Penjelasan dengan langkah-langkah:
Soal b
[tex] {7}^{ {x}^{2} - 3 x- 10 } = {49}^{x + 2} \\ {7}^{ {x}^{2} - 3x - 10 } = {7}^{2(x + 2)} \\ {7}^{ {x}^{2} - 3x - 10 } = {7}^{2x + 4} \\ { x}^{2} - 3x - 10 = 2x + 4 \\ {x}^{2} - 5x - 14 = 0 \\ (x - 7)( x + 2) \\ x = 7 \: atau \: x = - 2[/tex]
Soal c
[tex] {9}^{ {x}^{2} + x} = {27}^{ {x}^{2} - 1 } \\ { {3}^{2} }^{( {x}^{2} + x)} = { {3}^{3} }^{( {x}^{2} - 1 )} \\ {3}^{{2x}^{2} + 2x } = {3}^{ {3x}^{2} - 3 } \\ {2x}^{2} + 2x = {3x}^{2} - 3 \\ {x}^{2} - 2x - 3 = 0 \\ (x - 3)(x + 1) = 0 \\ x = 3 \: atau \: x = - 1[/tex]
Semoga membantu
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